# First puzzle

This puzzle is an implementation of Conway’s Game of Life but with lights. Our puzzle input is a 100 x 100 light grid where the # means on and “.” means off. We need to “animate” the lights. That means we need to calculate the next light state based on the previous state using the following rules:

• A light stays on if 2 or 3 neighbors are on. It turns off otherwise.
• A light off turns on if three neighbors are on. It continues off otherwise.
• To model the corners light that has fewer neighbors, we could consider the 100 x 100 lights surrounded by off lights. For example, for the lights at the top-left corner, position (0,0), to turn on, the lights at (1,0), (0,1) and (1,1) must be on.

The puzzle solution is to find how many lights are on after 100 iterations.

First some, input parsing:

To calculate the next state of lights we can fold the initial state applying the rules to calculate it as many times as the iteration number (100). When we have the final state, we can flatten and sum the lights to get to how many lights are on:

# Second puzzle

For the second puzzle, there is an additional rule:

• The corner lights are always one.

We can proceed with the same approach, but changing the folding binary function to keep the corners on all the time:

You can find this code along with my input and puzzle answers at here.

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Written by Darien Martinez Torres on 18 March 2016